# Download Cyclic Modules and the Structure of Rings by S.K. Jain PDF

By S.K. Jain

This targeted and finished quantity presents an updated account of the literature with reference to choosing the constitution of jewelry over which cyclic modules or right cyclic modules have a finiteness or a homological estate. The finiteness stipulations and homological houses are heavily interrelated within the feel that both speculation induces the opposite in a few shape. this can be the 1st ebook to convey all of this crucial fabric at the topic together.

Over the final 25 years or extra a variety of mathematicians have investigated jewelry whose issue earrings or issue modules have a finiteness or a homological estate. They made very important contributions resulting in new instructions and questions, that are indexed on the finish of every bankruptcy for the good thing about destiny researchers. there's a wealth of fabric at the subject that's mixed during this e-book, it comprises greater than 2 hundred references and isn't claimed to be exhaustive.

This booklet will entice graduate scholars, researchers, and pros in algebra with an information of easy noncommutative ring concept, in addition to module thought and homological algebra, akin to a one-year graduate direction within the idea of jewelry and modules.

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By the choice of A, there exist x and y in R with a − axa ∈ I and a − aya ∈ J. Thus a − a(x + y − xay)a = (a − axa) − aya + (axa)ya and so a − a(x + y − xay)a ∈ I. Similarly a − a(x + y − xay)a ∈ J. Therefore, a − a(x + y − xay)a ∈ I ∩ J. But, since I ∩ J = 0, we have a − a(x + y − xay)a = 0. This contradicts the choice of A. Consequently, R is von Neumann regular. The converse is obvious. 22 If R is two-sided noetherian and each prime factor ring of R is von Neumann regular, then R/N (R) is von Neumann regular and N (R) is nilpotent.

Suppose B is not semisimple. There exists an F ⊂e B. We get an inﬁnite direct sum T1 = ⊕α∈Λ Fα with Fα ⊂e Bα . Then, every cyclic subfactor of R/T1 is proper, for otherwise, a complement of T in R will contain a copy of B, and that will give a contradiction. Hence R/T1 is of ﬁnite Goldie dimension. 7). Hence B is semisimple. 13 Let R be a right P CCS-ring.

From this, we conclude that S is a semiprimary ring. It follows that S is an artinian ring since S has left and right restricted minimum condition. Therefore R is a noetherian ring. A ring R is said to satisfy the restricted right socle condition (RRS for short) if for each essential right ideal E (= R), R/E has nonzero socle. A ring R is called a right QI-ring if each quasi-injective right R-module is injective. Boyle proved that a right QI-ring is right noetherian, and conjectured that every right QI-ring is hereditary [30].